I am collecting process ids only with grepping into $new and process
all process ids and then save original list of process ids into $old,
this second time I have two lists $new (which has lastest process ids,
some may be new ones added) and $old (which holds process ids that I
have already processed)  I am running
in look like this every 5 seconds 'while process.... true  do sleep 5
done '

Now my question is, how I can get the latest list of process ids as
following in korn shell i.e.

$latest=($new-$old) # I don't want to process the old ids again
therefore
                    # $latest will have only process ids that need to
be
                    # processed.

Thanks very much in advance for your help.

On 17 Sep 2001 15:03:28 -0700, sethi_san...@hotmail.com (b10) wrote:

Hi,

You could use a sort of hash array by setting variables 'tab_[PID]'
with the values of the $old list then loop through values in the
$new list and see if their entries are present, when they aren't
the items are added to $latest. This will work in any bourne
shell and should be pretty fast;

#!/bin/sh
latest=
for i in $old
do
  eval tab_$i=1
done
for i in $new
do
  eval v=\$tab_$i
  [ -z "$v" ] && latest="$latest $i"
done
for i in $old
do
  eval tab_$i=
done

byefrom,

--
: ${L} # http://lf.8k.com:80

You might try something like this, it will give you PIDs that are unique
to either list, i.e. it will work only if $new is a superset of
$old.
      echo "$new$old" | sort | uniq -u

-- Context deleted.
-- more deletia

--
\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\
     Cal Dunigan      cdi           There is something fundamentally
       Consulting     Unix          wrong with a world in which Ken
       Modeling       Perl          Thompson lives in obscurity and
       Training       VHDL          Bill Gates is a famous billionaire.
//////////////////////////////////////////////////////////////////////