I want to write a script that exract text from data file i.e

% cat data

########
data 1 1002
EC
########
data 2 2345
data 3 Error
EC
########
data 4 Error
data 5 254225
data 6 336586
data 7 578641
EC
########

now I want to extract the data b/w ##### i.e.

% extract data
data 1
EC
data 2
data3
EC
.
.
.
data 7

someone told me that I can use awk for this purpose but I don't know
how to prgramme in awk, so if suggesting me the solution in awk please
tell me also where can I get a good tutorial on (except for man
command bcoz it is very difficult to understand without examples).

Thank you all

perl -ne's/^#+$//;/\S/&&print' data

John
--
use Perl;
program
fulfillment

awk '/^#/ {next} {$3="";print}' infile

got to the gnu site and read about gawk

Chuck Demas

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"MIA" <sfr...@hotmail.com> a crit dans le message de news:
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In shell, using cut and grep:

  grep -v '#' data | cut -f 1-2 -d\

In sed

  sed '/#/d;s/ /#/2;s/#.*//' data

Laurent

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Go to :
Effective AWK Programming : A User's Guide for GNU Awk
http://www.lns.cornell.edu/public/COMP/info/gawk/gawk_toc.html

--
Onismus Radebe

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  "MIA" <sfr...@hotmail.com> wrote in message
news:5f5518d0.0307281246.e0b70da@posting.google.com...

Go to :
Effective AWK Programming : A User's Guide for GNU Awk
http://www.lns.cornell.edu/public/COMP/info/gawk/gawk_toc.html

--
Onismus Radebe

For this task you could simply use:
grep -v '^#' data

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