Hi!

the (bash) shell-script

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#!/bin/sh
export blubber=blabber

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should set the variable blubber to the value blabber in the shell, from
where I call the script...but it DOESN'T...any suggestions?

Thanks in advance,

Holger Hartmann

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Yes, invoke it differently.  Do either
source scriptname
        or
. scriptname

Either one will run the script in the current shell, and not a sub-shell.

Mark Post

Postmodern Consulting
Information Technology and Systems Management Consulting
To send me email, replace 'nospam' with 'home'.

No it should not.
It should set the variable blubber in the shell it is running.
Running a script starts a new shell in which the script is executed.
If the script finishes, the shell it ran in is killed.

If you want it to run in your current shell, you'll need to source it.

Eric

Firstly, no, it shouldn't (and can't) set anything in a separate calling
process.

Either you want to source the script to be read by the current shell,
or you want to have the script return a value which can be assigned to a
variable by the calling process if it wishes to.

--
        Craig Macbride <cra...@earthling.net>
-----------------------http://www.nyx.net/~cmacbrid------------------------
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                to be ashamed of myself." - Captain Kremmen